지방에서 서울까지

str = input() result = "" for s in str: if s.isupper(): result += s.lower() else: result += s.upper() print(result)

def solution(t, p): answer = 0 ls = [] for i in range(len(t)): if len(t[i:i+len(p)]) != len(p) or int(t[i:i+len(p)]) > int(p): continue ls.append(t[i:i+3]) return len(ls)

def solution(number): answer = 0 for i in range(len(number)): for j in range(i+1, len(number)): for n in range(j+1, len(number)): if number[i] + number[j] + number[n] == 0: answer += 1 return answer

def solution(sizes): answer = 0 msize = [0, 0] for i in range(len(sizes)): sizes[i] = sorted(sizes[i]) if msize[0] < sizes[i][0]: msize[0] = sizes[i][0] if msize[1] < sizes[i][1]: msize[1] = sizes[i][1] return msize[0] * msize[1]

-- 코드를 입력하세요 SELECT A.REST_ID, B.REST_NAME, B.FOOD_TYPE, B.FAVORITES, B.ADDRESS, ROUND(AVG(REVIEW_SCORE), 2) AS SCORE FROM REST_REVIEW A INNER JOIN (SELECT REST_ID, REST_NAME, FOOD_TYPE, FAVORITES, ADDRESS FROM REST_INFO WHERE SUBSTR(ADDRESS, 1, 2) = '서울') B ON A.REST_ID = B.REST_ID GROUP BY 1 ORDER BY SCORE DESC , B.FAVORITES DESC

def solution(A: str, B: str) -> int: result = 0 while result != len(A): if A == B: return result A = A[-1] + A[:-1] result += 1 return -1

SELECT DISTINCT A.CART_ID FROM (SELECT CART_ID, NAME FROM CART_PRODUCTS WHERE NAME = 'Yogurt') A LEFT JOIN (SELECT CART_ID, NAME FROM CART_PRODUCTS WHERE NAME = 'Milk') B ON A.CART_ID = B.CART_ID WHERE A.NAME IS NOT NULL AND B.NAME IS NOT NULL

SELECT ID, NAME, HOST_ID FROM PLACES WHERE PLACES.HOST_ID IN (SELECT HOST_ID FROM (SELECT HOST_ID,COUNT(HOST_ID) AS H_CNT FROM PLACES GROUP BY HOST_ID HAVING H_CNT >= 2)A)

def solution(s): answer = s num_s = {'zero':0, 'one':1, 'two':2, 'three':3, 'four':4, 'five':5, 'six':6, 'seven':7, 'eight':8, 'nine':9} for item in num_s.items(): answer = answer.replace(item[0], str(item[1])) return int(answer)

def solution(strings, n): strings = sorted(strings) answer = sorted(strings, key=lambda x:x[n]) return answer